| 1 | PRSALVU ; HISC/REL-Leave Length ;5/31/95  12:21
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| 2 |  ;;4.0;PAID;;Sep 21, 1995
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| 3 |  S Z=$G(^PRST(458.1,DA,0)) I $E(ENT,1,2)["D" G D
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| 4 |  I $P(Z,"^",7)="ML" G D
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| 5 | H ; Calculate Hours
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| 6 |  S TYL="H",D1=$P(Z,"^",3) D PP^PRSAPPU
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| 7 |  I D1=$P(Z,"^",5) G 1
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| 8 |  ; Calculate first day
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| 9 |  D TC S X1=$G(^PRST(457.1,+TC,1))
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| 10 |  S X2="MID" F K=1:3 Q:$P(X1,"^",K)=""  S %=$P(X1,"^",K+2) I $S('%:1,1:$P($G(^PRST(457.2,%,0)),"^",2)="RG") S X2=$P(X1,"^",K+1)
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| 11 |  S X=$P(Z,"^",4)_"^"_X2 D CNV^PRSATIM S TIM=$P(Y,"^",2)-$P(Y,"^",1)/60 S:TIM<0 TIM=0
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| 12 |  D RG I TIM>RG S TIM=RG
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| 13 |  E  S X1=$P(X1,"^",3) I X1,TIM>4.75 S TIM=TIM-(X1/60)
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| 14 |  ; Calculate intermediate days
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| 15 | 0 S DAY=DAY+1 S:DAY=15 DAY=1,PPI=$S('PPI:PPI,$D(^PRST(458,PPI+1)):PPI+1,1:"")
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| 16 |  S X1=D1,X2=1 D C^%DTC S D1=X I X'<$P(Z,"^",5) G L
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| 17 |  D TC,RG S TIM=TIM+RG G 0
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| 18 | L ; Calculate last day
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| 19 |  D TC S X1=$G(^PRST(457.1,+TC,1))
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| 20 |  S X2="MID" F K=1:3 Q:$P(X1,"^",K)=""  S %=$P(X1,"^",K+2) I $S('%:1,1:$P($G(^PRST(457.2,%,0)),"^",2)="RG") S X2=$P(X1,"^",K) Q
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| 21 |  S X=X2_"^"_$P(Z,"^",6) D CNV^PRSATIM S T1=$P(Y,"^",2)-$P(Y,"^",1)/60 S:T1<0 T1=0
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| 22 |  D RG I T1>RG S T1=RG
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| 23 |  E  S X1=$P(X1,"^",3) I X1,T1>4.75 S T1=T1-(X1/60)
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| 24 |  S TIM=TIM+T1 G S
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| 25 | 1 ; One Day
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| 26 |  S X=$P(Z,"^",4)_"^"_$P(Z,"^",6) D CNV^PRSATIM S TIM=$P(Y,"^",2)-$P(Y,"^",1)/60
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| 27 |  D TC,RG I TIM>RG S TIM=RG G S
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| 28 |  S X1=$P(X1,"^",3) I X1,TIM>4.75 S TIM=TIM-(X1/60)
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| 29 |  G S
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| 30 | TC ; Get tour
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| 31 |  I PPI S X1=$G(^PRST(458,PPI,"E",DFN,"D",DAY,0)),TC=$P(X1,"^",2)
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| 32 |  E  S PPI=$P(^PRST(458,0),"^",3),X1=$G(^PRST(458,PPI,"E",DFN,"D",DAY,0)),TC=$P(X1,"^",2) I $P(X1,"^",3),$P(X1,"^",4) S TC=$P(X1,"^",4)
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| 33 |  Q
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| 34 | RG ; Get X1,RG
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| 35 |  S X1=$G(^PRST(457.1,+TC,0)),RG=$P(X1,"^",6) Q:RG'=""  I TC<5 S RG=0 Q
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| 36 |  I $E(AC,2)=1,NH=48 S RG=12 Q
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| 37 |  S RG=$S(NH>80:24,NH<80:NH\10,1:8) Q
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| 38 | D ; Calculate Days
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| 39 |  S X2=$P(Z,"^",3),X1=$P(Z,"^",5) I 'X1!('X2) Q
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| 40 |  D ^%DTC S TIM=X+1,TYL="D" G S
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| 41 | S ; Store length
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| 42 |  S $P(^PRST(458.1,DA,0),"^",15,16)=TIM_"^"_TYL Q
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