| 1 | SPNGFIMM ;WDE/SD OUTCOME GRID FOR FIM'S 9/19/2002 | 
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| 2 | ;;2.0;Spinal Cord Dysfunction;**19**;01/02/1997 | 
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| 3 | CALC ;  Create the values | 
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| 4 | ;called from spngfimh  gets the scores to plug into the grids | 
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| 5 | ;  da = the current fim with a score of 4,5,9 or 10 | 
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| 6 | ;  now get the START fim | 
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| 7 | S SPNGFIS="" | 
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| 8 | S SPNXX=0 F  S SPNXX=$O(^TMP($J,SPNXX)) Q:SPNXX=""  S SPNYY=0 F  S SPNYY=$O(^TMP($J,SPNXX,SPNYY)) Q:SPNYY=""  S SPNZZ=0 F  S SPNZZ=$O(^TMP($J,SPNXX,SPNYY,SPNZZ)) Q:SPNZZ=""  D  Q:+SPNGFIS | 
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| 9 | .I $P(^SPNL(154.1,SPNZZ,0),U,2)=2 I 16[$P(^SPNL(154.1,SPNZZ,2),U,17) S SPNGFIS=SPNZZ | 
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| 10 | ;SPNGFIS IS THE FIM START RECORD | 
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| 11 | Q:$D(SPNGFIS)=0 | 
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| 12 | Q:SPNGFIS="" | 
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| 13 | ;total gain | 
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| 14 | S SPNR1C1A=$$GET1^DIQ(154.1,DA_",",999.05) | 
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| 15 | S SPNR1C1B=$$GET1^DIQ(154.1,SPNGFIS_",",999.05) | 
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| 16 | S SPNR1C1=SPNR1C1A-SPNR1C1B | 
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| 17 | ;Total efficiency | 
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| 18 | S SPNR1C2A=$$GET1^DIQ(154.1,DA_",",999.08) | 
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| 19 | I $G(SPNR1C2A)>0 S SPNR1C2=SPNR1C1/SPNR1C2A S SPNR1C2=$E(SPNR1C2,1,4) | 
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| 20 | I $G(SPNR1C2A)=0 S SPNR1C2="N/A" | 
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| 21 | ;Motor Gain | 
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| 22 | S SPNR1C3A=$$GET1^DIQ(154.1,DA_",",999.03) | 
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| 23 | S SPNR1C3B=$$GET1^DIQ(154.1,SPNGFIS_",",999.03) | 
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| 24 | S SPNR1C3=SPNR1C3A-SPNR1C3B | 
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| 25 | ;Motor efficiency | 
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| 26 | S SPNR1C4A=$$GET1^DIQ(154.1,DA_",",999.08) | 
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| 27 | I $G(SPNR1C4A)>0 S SPNR1C4=SPNR1C3/SPNR1C4A S SPNR1C4=$E(SPNR1C4,1,4) | 
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| 28 | I $G(SPNR1C4A)=0 S SPNR1C4="N/A" | 
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| 29 | ;Cognitive Gain | 
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| 30 | S SPNR1C5A=$$GET1^DIQ(154.1,DA_",",999.04) | 
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| 31 | S SPNR1C5B=$$GET1^DIQ(154.1,SPNGFIS_",",999.04) | 
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| 32 | S SPNR1C5=SPNR1C5A-SPNR1C5B | 
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| 33 | ;Cognitive Efficiency | 
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| 34 | S SPNR1C6A=$$GET1^DIQ(154.1,DA_",",999.08) | 
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| 35 | I $G(SPNR1C6A)>0 S SPNR1C6=SPNR1C5/SPNR1C6A S SPNR1C6=$E(SPNR1C6,1,4) | 
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| 36 | I $G(SPNR1C6A)=0 S SPNR1C6="N/A" | 
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